More attempts to determine when addition is associative
Somebody hit me with bug reports on this. :) Refs #300
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@@ -1965,7 +1965,7 @@ merge(Compressor.prototype, {
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self = make_node(AST_Binary, self, {
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operator: "+",
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left: make_node(AST_String, null, {
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value: self.left.getValue() + self.right.left.getValue(),
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value: "" + self.left.getValue() + self.right.left.getValue(),
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start: self.left.start,
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end: self.right.left.end
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}),
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@@ -1981,12 +1981,33 @@ merge(Compressor.prototype, {
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operator: "+",
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left: self.left.left,
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right: make_node(AST_String, null, {
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value: self.left.right.getValue() + self.right.getValue(),
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value: "" + self.left.right.getValue() + self.right.getValue(),
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start: self.left.right.start,
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end: self.right.end
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})
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});
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}
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if (self.left instanceof AST_Binary
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&& self.left.operator == "+"
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&& self.left.is_string(compressor)
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&& self.left.right instanceof AST_Constant
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&& self.right instanceof AST_Binary
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&& self.right.operator == "+"
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&& self.right.left instanceof AST_Constant) {
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self = make_node(AST_Binary, self, {
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operator: "+",
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left: make_node(AST_Binary, self.left, {
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operator: "+",
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left: self.left.left,
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right: make_node(AST_String, null, {
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value: "" + self.left.right.getValue() + self.right.left.getValue(),
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start: self.left.right.start,
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end: self.right.left.end
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})
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}),
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right: self.right.right
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});
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}
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}
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}
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return self.evaluate(compressor)[0];
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@@ -69,6 +69,6 @@ constant_join_2: {
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var e = [ "foo", "bar", boo(),
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"foo+1+2+3+bar",
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"baz", "x", "y" ].join("really-long-separator");
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var f = "strstr" + variable + "foobar" + ("moo" + foo);
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var f = "strstr" + variable + "foobarmoo" + foo;
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}
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}
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22
test/compress/concat-strings.js
Normal file
22
test/compress/concat-strings.js
Normal file
@@ -0,0 +1,22 @@
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concat_1: {
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options = {
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evaluate: true
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};
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input: {
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var a = "foo" + "bar" + x() + "moo" + "foo" + y() + "x" + "y" + "z" + q();
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var b = "foo" + 1 + x() + 2 + "boo";
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var c = 1 + x() + 2 + "boo";
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// this CAN'T safely be shortened to 1 + x() + "5boo"
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var d = 1 + x() + 2 + 3 + "boo";
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var e = 1 + x() + 2 + "X" + 3 + "boo";
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}
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expect: {
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var a = "foobar" + x() + "moofoo" + y() + "xyz" + q();
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var b = "foo1" + x() + "2boo";
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var c = 1 + x() + 2 + "boo";
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var d = 1 + x() + 2 + 3 + "boo";
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var e = 1 + x() + 2 + "X3boo";
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}
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}
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